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WINGBEATS
SOLUTIONS
1. Which of these
combinations would "make the most flaps"?
a) 1 hummingbird
flapping for 45 seconds (sec) = 3,150 wb
45 sec x 700 wb/10
sec. = 31,500/10 = 3,150 wb
b)10 crows
flapping for 65 sec = 1,300 wb
650 sec x 20 wb/10
sec = 13,000/10 = 1,300 wb
c) 4 kestrels,
1 chickadee, 1 owl and 1 eagle flapping for 3 min. = 9,324 wb*
4 kestrels .
. .
720 sec x 47 wb/10 sec = 33,840/10 = 3,384 wb
1 chickadee .
. .
180 sec x 270 wb/10 sec = 48,600/10 = 4,860 wb
1 owl . . .
180 sec x 35 wb/10 sec = 6,300/10 = 630 wb
1 eagle . . .
180 sec x 25 wb/10 sec = 4,500/10 = 450 wb Total = 9,324 wb*
d) 4 starlings
flapping for 5 minutes (min) = 5,400 wb
1,200 sec x 45
wb/10 sec = 54,000/10 = 5,400 wb
2. If a owl, kestrel,
and eagle each flew in the same direction going 30 miles per hour, how
many times would each one flap if:
a. the owl flew
15 miles = 6,300 wb
15 miles x 1 hour (hr)/30 miles x 60 min/1 hr x 60 sec/1 min x 35 wb/10
sec =
1,890,000 = 6,300 wb
b. the kestrel
flew 45 miles = 25,380 wb
45 miles x 1 hr/30 miles x 60 min/1 hr x 60 sec/1 min x 47 wb/10 sec
= 7,614,000 = 25,380 wb
c. the eagle flew
90 miles = 27,000 wb
90 miles x 1 hr/30 miles x 60 min/1hr x 60 sec/ 1 min x 25 wb/10 sec
= 8,100,000 = 27,000 wb
3. If a raven,
kestrel, owl, vulture, chickadee, and hummingbird each flapped their wings
for 20 seconds, how many total flaps would there be?
raven . . . 20
sec x 20 wb/10 sec = 400/10 = 40 wb
kestrel . . . 20
sec x 47 wb/10 sec = 940/10 = 94 wb
owl . . . 20 sec
x 35 wb10 sec = 700/10 = 70 wb
vulture . . . 20
sec x 25 wb/10 sec = 500/10 = 50 wb
chickadee . . .
20 sec x 270 wb/10 sec = 5400/10 = 540 wb
hummingbird . .
. 20 sec x 700 wb/10 sec = 14,000/10 = 1,400 wb 1
Total = 2,194
wb
4. How many wingbeats
would you get in one minute from:
a. hummingbird . .
. 60 sec x 700 wb/10 sec = 42000/10 = 4,200 wb 10 sec 10
b. chickadee . . .
60 sec x 270 wb/10 sec = 16200/10 = 1,620 wb 10 sec 10
c. pigeon . . . 60
sec x 30 wb/10 sec = 1800/10 = 180 wb 10 sec 10
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